If cosA-sinA=√2sinA then show that( cosA-sinA)
shyam108:
kauno sol
Answers
Answered by
0
Sina+Cosa=√2
Squaring on both sides
(SinA + cosA)^2= (√2)^2
Sin^2+cos^2+2sinAcosA=2
1-sin2A =2
Sin2A=1-2
Sin2A= -1
2A= -1
2A= -(sin 90)
A= -(90/2)
A= -45
-cos 45-(-sin45)
-1/√2-(-1/√2)
-1/√2+1/√2
=0
Squaring on both sides
(SinA + cosA)^2= (√2)^2
Sin^2+cos^2+2sinAcosA=2
1-sin2A =2
Sin2A=1-2
Sin2A= -1
2A= -1
2A= -(sin 90)
A= -(90/2)
A= -45
-cos 45-(-sin45)
-1/√2-(-1/√2)
-1/√2+1/√2
=0
Similar questions