Question

- If cosec 0 = √2 , find the value of :1/tanA + sinA/1+cosA​

Answer 1

Answer:      (√2+2)/(√2+1)

Step-by-step explanation:

cosecA = √2  

or, cosecA = cosec 45°  

or,       A     =     45°

Hence, 1/tanA +sinA /(1+cos A) = 1/1 + (1/√2)/ (1+1/√2)

                                                   =   1+ 1/(√2+1) = (√2+2)/(√2+1)