If cosec 0 + cote = k, then prove that cos o k-1 k? +1'
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Answer:
Step-by-step explanation:
Given,
cosecθ+cotθ=k
sinθ
1
+
sinθ
cosθ
=k
sinθ
1+cosθ
=k
1+cosθ=ksinθ
Squaring both side,
(1+cosθ)
2
=k
2
sin
2
θ
(1+cosθ)
2
=k
2
(1−cos
2
θ)
(1+cosθ).(1+cosθ)=k
2
(1+cosθ)(1−cosθ)
1+cosθ=k
2
(1−cosθ)
1+cosθ=k
2
−k
2
cosθ
1+(1+k
2
)cosθ=k
2
(1+k
2
)cosθ=k
2
−1
cosθ=
k
2
+1
k
2
−1
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