Question

If cosec θ = 13/12, then value tan θ is

Answer 1

Answer:

2 2/5

Step-by-step explanation:

cosec0 = h/p= 13/12

let h= 13k and p= 12k

h^2= p^2+b^2

13^2k^2= 12^2k^2+b^2

169k^2=144k^2 +b^2

√169k^2-144k^2= b

b= 5k

tan 0 = p/b

= 12k/5k

= 12/5

= 2 2/5