Question

If cosecθ=13/5, find tanθ and cosθ.

Answer 1

cosec A = 13/5=h/p
by pythagoreus theorem
(h)2=(p)2+(b)2
(13)2=(5)2+(b)2
169_25=(b)2
144=(B)2
12×12=(B)2
B=12
TAN A=P/B=5/12
COS A =B/H=12/3