IF cosec Ф = 3x and cot Ф = 3/x , then find the value of [x²+1/x²]
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4
Answer:
x = coseca/3
1/x = cota/3
(x²-1/x²) = (x+1/x)(x-1/x)
= (coseca/3 + cota/3)(coseca/3 - cota/3)
= 1/9 (coseca+ cota)(coseca - cota)
= 1/9 (cosec²a - cot²a)
= 1/9 (cot²a +1 - cot²a)
= 1/9 (1)
= 1/9
I hope you understand the approach.
All the best!
Read more on Brainly.in - https://brainly.in/question/1240048#readmorex = coseca/3
1/x = cota/3
(x²-1/x²) = (x+1/x)(x-1/x)
= (coseca/3 + cota/3)(coseca/3 - cota/3)
= 1/9 (coseca+ cota)(coseca - cota)
= 1/9 (cosec²a - cot²a)
= 1/9 (cot²a +1 - cot²a)
= 1/9 (1)
= 1/9
I hope you understand the approach.
All the best!
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3
Answer:
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sahib bro
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