Question

If cosec |=3x and cot |=3/x. then find the value of (x2-1/x2)

Answer 1

Answer:

since it is given that 3x=cosec theta and 3/x=cot theta

so,x=cosec theta/3 & 1/x=cot theta/3

so,cosec theta^2/9 - cot^2/9

1/9(cosec theta^2 - cot theta^2). -(1)

as we know that 1 + cot theta^2=cosec theta^2

1=cosec theta^2 - cot theta ^2. -(2)

putting value of (2) in (1)

1/9

Answer 2

$x = \frac{cosec}{3}$

$\frac{1}{x } = \frac{cot}{3}$

${x}^{2} - \frac{1}{ {x}^{2} } = {cosec}^{2} - {cot \div 9}$

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$\frac{1}{9}$