Math, asked by VijayaLaxmiMehra1, 1 year ago

If cosec A = 2, find the value of
1 / tanA + sinA / 1+cosA

Standard:- 10

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Answers

Answered by BrainlyQueen01
76
Hey mate!

Here's ur answer dear:-)
_____________________
_____________________

Refer to the attachment above✔✔

Hope it helps:)

☺☺
Attachments:

shubhamrajput86: By short tricks
AJAYMAHICH: achhaa.....but exam me tricks nhi methods chahiye hote hai......
AJAYMAHICH: trick only for used in competitive exams
shubhamrajput86: Tricks are only for those whom are preparing for competitive exams
AJAYMAHICH: hmmm right
shubhamrajput86: yup
BrainlyQueen01: thnx destroyer or sachin bhai :)
BrainlyQueen01: thnx harshmodi (:
fanbruhh: grt
Answered by Anonymous
89
Hey Friends!!

Here is your answer↓⬇

⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇

 \bf \sf{It \: is \: given \: that:-)}

 \bf \sf{ \: Cosec A = 2.}

▶⏩ To Find:-)

 \huge \boxed{= \frac{1}{ \tan(x) } + \frac{ \sin(x) }{1 + \cos(x) } .}

 \bf \tan(x) = \frac{1}{ \sqrt{3} }.
 \bf \: \sin(x) = \frac{1}{2} .
 \bf \: \cos(x) = \frac{ \sqrt{3} }{2} .

▶⏩ Now, put the value in the question.

 \huge \bf = \frac{1}{ \frac{1}{ \sqrt{3} } } + \frac{1}{2} \div \frac{1 + \sqrt{3} }{2} .

 \huge \bf = \sqrt{3} + \frac{1}{2} \div \frac{2 + \sqrt{3} }{2} .

 \huge \bf = \sqrt{3} + \frac{1}{2} \times \frac{2}{2 + \sqrt{3} } .

 \huge \bf = \sqrt{3} + \frac{1}{2 + \sqrt{3} } .

 \huge \bf = \sqrt{3} + \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} } .

 \huge \bf = \sqrt{3} + \frac{2 - \sqrt{3} }{ ({2})^{2} - {( \sqrt{3} )}^{2} }

 \huge \bf = \sqrt{3} + \frac{2 - \sqrt{3} }{4 - 3} .

 \huge \bf = \sqrt{3} + \frac{2 - \sqrt{3} }{1} .

 \huge \bf = \sqrt{3} + 2 - \sqrt{3} .

 \huge \boxed{ = 2.}

✅✅Hence, it is founded ✔✔.

 \huge \boxed{THANKS}

 \huge \bf \underline{Hope \: it \: is \: helpful \: for \: you}
Attachments:

VijayaLaxmiMehra1: you have directly write
Anonymous: Now, you can see
AJAYMAHICH: nice answer_______
VijayaLaxmiMehra1: Thanks :))
Anonymous: u welcome
kavya139: nyc ans dear... ( ^_^ )
Anonymous: thanks bahn ji
fanbruhh: good one sachin
Anonymous: thanks bhai
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