Math, asked by prannav88, 6 months ago

If cosec A = 2, sec B = 1, Find A+B and A-B.​

Answers

Answered by ravi2303kumar
4

Answer:

A+B = 30°

A-B = 30°

Step-by-step explanation:

Given, cosecA = 2

=> 1/sinA = 2

=> sin A = 1/2

=> A = sin⁻¹(1/2)

=> A = 30°

also given that

secB = 1

=> 1/cosB = 1

=> cosB = 1

=> B =  cos⁻¹(1)

=> B = 0°

so, A+B = 30°+0° = 30°

&   A-B = 30°-0° = 30°

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