If cosec A= 2x & cot A=21x, then 1
the value of 2 {(x+1/x)(x-1/x)} is
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Given: cosec theta =2x and cot there=2/x
cosec theta = 2x. cot theta =2/x
squaring both sides. squaring both side
cosec² theta =4x². cot² theta =4/x²
cosec² theta - cot² theta =1
4x²-4/xx=1
4(x²-1/x²) =1
2(x²-1/x²) =1/2
hence proved
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