Question

if cosec A =7/4 prove that 1 + 10 square = sec square A .
pls answer it....​

Answer 1

=>we need to prove that

1+tan²A = sec²A

=>Given that Cosec A = 7/4

=>Proof-of-concept

Cosec A = 7/4 = H/P

Let H = 7k and P = 4k

Using Pythagoras theorem,

H² = P²+B²

(7k)² = (4k)²+B²

B² = 49k²-16k²

B = √(33k²) = √(33) k

LHS: 1+tan²A

= 1+(P/B)²

= 1+(4/√33)²

= 1+(16/33) = 49/33

RHS: sec²A

= (H/B)²

= (7/√33)² = 49/33

LHS = RHS H.proved

Answer 2

Cosec A = 7/4 = H/P => H = 7k and P = 4k. Using Pythagoras theorem, H² = P²+B² (7k)² = (4k)²+B² => B² = 49k²-16k²