Question

if cosec A =7/4,prove that 1+tan²A=sec²A

Answer 1

Cosec A = 7/4 => hypotenuse = 7x and perpendicular = 4x now find base in the triangle by pythagoreous theorem base^2 = 49 x^2 - 16x^2 = 33x ^2 now 1+ tan^2A = 1 + 16/33 = 49 /33 = sec^2 A proved