Question

If cosec theta =13\5, then cot theta =​

Answer 1

Answer:

$cosec \: theta = \frac{13}{5} = \frac{h}{p} \\ pythagoras \: theoram \: \\ h {}^{2} = p {}^{2} + b {}^{2} \\ (13) {}^{2} = (5) {}^{2} + b {}^{2} \\ 169 - 25 = b {}^{2} \\ 144 = b {}^{2} \\ b = \sqrt{144} \\ b = 12$

$\cot \: theta \: = \frac{b}{p} = \frac{12}{5}$

Answer 2

HERE IS UR ANSWER DEAR,

cosec theta = 1/ sin theta = hyp / opp = 13 /5

therefore

opposite side = 5

hypotenuse = 13

and

cot theta = adj/ opp...

so in order to find

value of another side of the triangle

use Pythagoras theorem ,

13² = 5²+ x²

169= 25 + adj²

adj² = 169- 25

adj² = 144

adj = √144

adj. = 12

so ,

cot theta = adj/opp = 12/5