if cosec theta = 2 and cot theta =√3p where thera is an acute angle then p=?
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Hi,
Here is your answer !
_____________________________
Given that,
cosecθ = 2
cosecθ = cosec30° [ ∵ cosec30° = 2 ]
→ θ = 30°
Also ,
cotθ = √3 p [ Given ]
cot30° = √3 p
→ 2/√3 = √3 p [ ∵ cot30° = 2/√3 ]
→ ( 2/√3 ) × ( 1/√3 ) = p
→ p = (2×1) / (√3×√3)
→ p = 2/3
Here is your answer !
_____________________________
Given that,
cosecθ = 2
cosecθ = cosec30° [ ∵ cosec30° = 2 ]
→ θ = 30°
Also ,
cotθ = √3 p [ Given ]
cot30° = √3 p
→ 2/√3 = √3 p [ ∵ cot30° = 2/√3 ]
→ ( 2/√3 ) × ( 1/√3 ) = p
→ p = (2×1) / (√3×√3)
→ p = 2/3
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