if cosec theta =25/7,then find cot theeta
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60
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Given, cosec ∅ = 25 / 7
we know, cosec ∅ = H / P (where, H = hypotenuse and P = perpendicular)
Now, cot ∅ = ?
To find cot∅, draw a triangle ABC where AB is the base, AC is the perpendicular and CD is the hypotenuse of the triangle.
Now ,
AC (P) = 7
CD (H) = 25
AB (B) = ?
Using P.G.T. we can find AB
So, (AB)² = (CD)² - (AC)²
AB = √{ (25)² - (7)² }
AB = √ (625 - 49)
AB = √576
AB = 24
Now, we know that, cot∅ = B/P
∴ cot∅ = 24 /7
Given, cosec ∅ = 25 / 7
we know, cosec ∅ = H / P (where, H = hypotenuse and P = perpendicular)
Now, cot ∅ = ?
To find cot∅, draw a triangle ABC where AB is the base, AC is the perpendicular and CD is the hypotenuse of the triangle.
Now ,
AC (P) = 7
CD (H) = 25
AB (B) = ?
Using P.G.T. we can find AB
So, (AB)² = (CD)² - (AC)²
AB = √{ (25)² - (7)² }
AB = √ (625 - 49)
AB = √576
AB = 24
Now, we know that, cot∅ = B/P
∴ cot∅ = 24 /7
Answered by
6
Answer:
cosec theta =25/7
cosec theta =hypotenuse /opposite side
AC =25. (hypotenuse)
BC =7. (opposite side)
AB=?
By Pythagoras theorem
AB= √25^2-7^2
=√625-49
=√576
=24
therefore cot theta =adjacent side/opposite side
=24/7
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