if cosec theta =√5 find the value of 2-sin^2theta - cos^2theta
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cosecΘ=5
cosecΘ=PH=5
Thus, H=5,P=1
Using Pythagoras Theorem,
H2=P2+B2
(5)2=12+B2
5=1+B2
B=2
Now, 2−sin2Θ−cos2Θ
= 2−(HP)2−(HB)2
= 2−(51)2−(52)2
= 2−51−54
= 2−1
= 1
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