If cosec theta - cot theta = 1/3 then find the value of ( cosec theta + cot theta)
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cosec square theta-cot square theta-cot =1
cosec theta +cot theta =1/cosec theta -cot theta
cosec theta +cot theta =3
(a square-b square)=(a+b)(a-b)
cosec theta +cot theta =1/cosec theta -cot theta
cosec theta +cot theta =3
(a square-b square)=(a+b)(a-b)
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