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if cosec theta + cot theta =5 then find the value of sec theta

Answers

Answered by ArthTripathi
2

Answer:

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Answered by sharonr
0

If cosec theta + cot theta = 5 then the value of sec\ \theta = \frac{13}{12}

Solution:

Given that,

cosec\ \theta + cot\ \theta = 5 ---- eqn\  1

We know that, by identity,

cosec^2\ \theta-cot^2\ \theta = 1

On\ expanding\ using\ a^2-b^2=(a+b)(a-b)

(cosec\ \theta + cot\ \theta)(cosec\ \theta - cot\ \theta) = 1

Substitute\ cosec\ \theta + cot\ \theta = 5

5(cosec\ \theta -cot\ \theta) = 1\\\\cosec\ \theta -cot\ \theta = \frac{1}{5}\\\\cosec\ \theta -cot\ \theta = 0.2 ------ eqn\ 2

Add eqn 1 and eqn 2

cosec\ \theta + cot\ \theta + cosec\ \thtea - cot\ \theta = 5 + 0.2\\\\2cosec\ \theta  = 5.2\\\\cosec\ \theta  = 2.6 = \frac{13}{5}

We know that,

sin\ \theta = \frac{1}{cosec\ \theta}

Therefore,

sin\ \theta = \frac{5}{13}

By identity,

cos^2\ \theta = 1 - sin^2\ \theta\\\\cos^2\ \theta = 1 - (\frac{5}{13})^2\\\\cos^2\ \theta = 1 - \frac{25}{169}\\\\cos^2\ \theta = \frac{144}{169}\\\\Take\ square\ root\ on\ both\ sides\\\\cos\ \theta = \frac{12}{13}\\\\We\ know\ that\\\\sec\ \theta= \frac{1}{cos\ \theta}\\\\sec\ \theta = \frac{13}{12}

Thus the value of sec theta is found

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