if cosec theta + cot theta is equal to P then cos theta is equal to p square minus one upon p square + 1
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Step-by-step explanation:
= (cosec + cot )^2 - 1/(cosec + cot)^2 +1
=cosec^2 + cot^2 +2coseccot -1/cosec^2 + cot^2 +2coseccot +1
=cosec^2 -1 +cot^2 +2coseccot/cosec^2 + 1 +cot^2 +2coseccot
=2cot(cot + cosec)/2cosec(cosec + cot)
=cot/cosec
=cos/sin*sin
=cos
HENCE PROVED
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