if cosec theta + cot theta = x , then show that cosec theta - cot theta = 1/x
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Thank you for asking this question. Here is your answer:
We will let theta = y
We have an identity that is cosec²(Y)-cot²(Y)=1
With the help of this now we will find the answer:
cosec²(Y)-cot²(Y)=1
[cosec(Y)+cot(Y)][cosec(Y)-cot(Y)]=1 {since a²-b²=[a+b][a-b]}
[cosec(Y)+cot(Y)][x]=1 {from given}
cosec(Y)+cot(Y)=1/x
If there is any confusion please leave a comment below.
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