if cosec theta=root 3-cot theta is:
a) 2/root3
b) root 3/2
c) root 3
d) 1/root 3
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Correct Question- if cosecθ = √3 - cotθ then find value of cosecθ or cotθ?
ATQ
cosecθ = √3 - cotθ
cosecθ + cotθ = √3 ...(1)
We know
cosec²θ - cot²θ = 1
(cosecθ + cotθ)(coseθ -cotθ) = 1
√3(cosecθ - cotθ) = 1
cosecθ - cotθ = 1/√3 ... (2)
Adding 1 and 2
2cosecθ = √3 + 1/√3 = (3 + 1)/√3 = 4/√3
cosecθ = 2/√3
Putting value of cosecθ = 2/√3 in equation 2 we get
cotθ = √3 - 2/√3 = (3 - 2)/√3
cotθ = 1/√3
Thus values of
cosecθ = 2/√3
cotθ = 1/√3
ATQ
cosecθ = √3 - cotθ
cosecθ + cotθ = √3 ...(1)
We know
cosec²θ - cot²θ = 1
(cosecθ + cotθ)(coseθ -cotθ) = 1
√3(cosecθ - cotθ) = 1
cosecθ - cotθ = 1/√3 ... (2)
Adding 1 and 2
2cosecθ = √3 + 1/√3 = (3 + 1)/√3 = 4/√3
cosecθ = 2/√3
Putting value of cosecθ = 2/√3 in equation 2 we get
cotθ = √3 - 2/√3 = (3 - 2)/√3
cotθ = 1/√3
Thus values of
cosecθ = 2/√3
cotθ = 1/√3
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