If cosec theta-sin theta=p and sec theta-cos theta=q, prove that p square ×q square (p square +q square +3)=1
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very good very good answer for examination
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[cosectheta-sintheta]^2+[sectheta-costheta]^2
[1\sintheta-sintheta] +[1\costheta-costhet]^2
[1-sintheta\sintheta]^2 + [1-costheta\costheta]^2
next you can solve by yourself:]
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