if cosec titha= √5,find the value of (i)2-sin2 thitha -cos2 thitha
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cosecΘ=
5
cosecΘ=
P
H
=
5
Thus, H=
5
,P=1
Using Pythagoras Theorem,
H
2
=P
2
+B
2
(
5
)
2
=1
2
+B
2
5=1+B
2
B=2
Now, 2−sin
2
Θ−cos
2
Θ
= 2−(
H
P
)
2
−(
H
B
)
2
= 2−(
5
1
)
2
−(
5
2
)
2
= 2−
5
1
−
5
4
= 2−1
= 1
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