Question

if cosec0 + cot0 = m , then find cot0

Answer 1

Answer:

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Step-by-step explanation:

$to \: find = \\ cot \: θ \: (in \: terms \: of \: m) \\ \\ so \: here \\ cosec \: θ + cot \: θ = m \\ ie \: \: cosec \: θ = m - cot \: θ \\ \\ so \: we \: know \: that \\ 1 + cot {}^{2} θ = cosec {}^{2} θ \\ = (m - cot \: θ) {}^{2} \\1 + cot {}^{2} \: θ = m {}^{2} + cot {}^{2} \: θ - 2m.cot \: θ \\ 1 = m {}^{2} - 2m.cot \: θ \\ 2m.cot \: θ = m {}^{2} - 1 \\ \\ hence \: then \\ cot \: θ = \frac{m {}^{2} - 1 }{2m}$