If cosecA = √10 then secA = ?
Answers
Step-by-step explanation:
sinA=1/√10
cosA=√1-sin^2A
put value and get answer
Step-by-step explanation:
We have,
cosecA=
Perpendicular
Hypotenuse
=
1
10
So, we draw a triangle ABC, right angled at B such that
Perpendicular =BC=1 unit and, Hypotenuse =AC=
10
units.
By Pythagoras theorem, we have
AC
2
=AB
2
+BC
2
⇒(
10
)
2
=AB
2
+1
2
⇒AB
2
=10−1=9
⇒AB=
9
=3
When we consider the trigonometric ratios of ∠ A , we have
Base =AB=3, Perpendicular =BC=1, and Hypotenuse =AC=
10
∴sinA=
Hypotenuse
Perpendicular
=
10
1
cosA=
Hypotenuse
Base
=
10
3
tanA=
Base
Perpendicular
=
3
1
secA=
Base
Hypotenuse
=
3
10
and, cotA=
Perpendicular
Base
=
1
3
=3
solution