Question

if cosecA =17/8,then 3cosA+2sinA/3tanA+2cotA​

Answer 1

Answer:

8296/11934

Explanation:

By Pythogoras Theorem:-

H² = B² + P²

17² = B² + 8²

17² - 8² = B²

289 - 64 = B²

225 = B²

√225 = B

15 = B

sinA = opp/hyp

sinA = 8/17

cosA = adj/hyp

cosA = 15/17

tanA = opp/adj

tanA = 8/15

cotA = adj/opp

cotA = 15/8

As per the question....

= (3cosA + 2sinA) / (3tanA+2cotA)

= (3[15/17] + 2[8/17]) / (3[8/15]) + 2[15/8])

= (45/17 + 16/17) / (24/17 + 30/8)

= (61/17) / (192 + 510/136)

= (61/17) / (702/136)

= (61x136) / (702x17)

= 8296/ 11934