If cosecA+cotA=11/2,then A=?
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1/ sinA - cosA / SinA
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625=√15625-1936/15625
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625=√15625-1936/15625=√13689/15625
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625=√15625-1936/15625=√13689/15625=117/125
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625=√15625-1936/15625=√13689/15625=117/125so now
1/ sinA - cosA / SinA = 1- cosA / sin A =11/2 = 2sin²A/2 /2sinA/2 CosA/2tanA/2=11/2sinA/2 = 11/5√5cosA/2= 2/5√5Now sinA=2*11/5√5*2/5√5= 44/125CosA =√1-1936/15625=√15625-1936/15625=√13689/15625=117/125so nowtanA=sinA/cosA = 44/117
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