if coseca=root3 find the value of 2sin^2a+3cot^2theta÷tan^2+cos^2a
Answers
Answered by
5
here cosec(a)=√3
so sin(a)=1/√3 &cos(a)=√2/√3
tan(a)=1/√2, cot(a)=√2
we have to find 2sin^2(a)+3cot^2a÷tan^2a+cos^2a
= 2×1/3+3×2÷1/2+2/3
=40/3 if no bracket
so sin(a)=1/√3 &cos(a)=√2/√3
tan(a)=1/√2, cot(a)=√2
we have to find 2sin^2(a)+3cot^2a÷tan^2a+cos^2a
= 2×1/3+3×2÷1/2+2/3
=40/3 if no bracket
Answered by
2
Answer:
answer 8
Step-by-step explanation:
Hope u like my answer
Attachments:
Similar questions