if cosectita=root10 find the value of all the ratios of tita
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Answer:
We have,
cosecA= PerpendicularHypotenuse=110
So, we draw a triangle ABC, right angled at B such that
Perpendicular =BC=1 unit and, Hypotenuse =AC= 10 units.
By Pythagoras theorem, we have
AC2=AB2+BC2
⇒(10)2=AB2+12
⇒AB2=10−1=9
⇒AB=9=3
When we consider the trigonometric ratios of ∠ A , we have
Base =AB=3, Perpendicular =BC=1, and Hypotenuse =AC= 10
∴sinA=HypotenusePerpendicular=101
cosA=Hypotenuse
Step-by-step explanation:
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