if cosO = 1/2 find the value of 2/1+tan^2O
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sin^2O+cos^2O=1
sinO=√(1-cos^2O)
=√(1-1/4)
=√(3/4)
sin^2O=3/4
& cos^2O=1/4
So tan^2O=sin^2O/ cos^2O=(3/4) / (1/4)=3
so 2/1+tan^2O=2/(1+3)
=2/4=1/2
HOPE IT HELPS....
sinO=√(1-cos^2O)
=√(1-1/4)
=√(3/4)
sin^2O=3/4
& cos^2O=1/4
So tan^2O=sin^2O/ cos^2O=(3/4) / (1/4)=3
so 2/1+tan^2O=2/(1+3)
=2/4=1/2
HOPE IT HELPS....
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