Question

if cosO = 1/2 find the value of 2/1+tan^2O

Answer 1

sin^2O+cos^2O=1
sinO=√(1-cos^2O)
=√(1-1/4)
=√(3/4)
sin^2O=3/4
& cos^2O=1/4
So tan^2O=sin^2O/ cos^2O=(3/4) / (1/4)=3
so 2/1+tan^2O=2/(1+3)
=2/4=1/2

HOPE IT HELPS....