Math, asked by Nishakumarichaurasia, 1 year ago

If cost of 5 chair and 4 table is 5600 and cost of 4 chair and 3 table is 4340 then find the cost of each table and chair

samyak201: i think the question is wrong

Nishakumarichaurasia: No its not wrong

Answers

Answered by devadakshan

Lets assume Cost of one chair be x
Lets assume Cost of one table be y

Given
"" "" "" "" ""
1) 5x + 4y = 5600 ......... (1)
2) 4x + 3y = 4340 ........... (2)

From (1)
"" "" "" "" ""
5x + 4y = 5600
5x = 5600-4y
x = (5600-4y) /5 .......... (3)

Substitute (3) in (2)
"" "" "" "" "" """"" "" "" ""
4x + 3y = 4340
4{ (5600 - 4y) /5 } + 3y = 4340
(22400 - 16y) / 5 + 3y = 4340
(22400 - 16y + 15y) /5 = 4340
22400 - y = 21700
y = 22400 - 21700
y = 700 ........(4)

Substitute (4) in (3)
"" "" "" "" "" "" "" "" "" "
x = (5600-4y) /5
x = 5600 - 2800 / 5
x = 2800 / 5
x = 560

Therefore,
" "" "" "" "" "'' ''"
Cost of chair = 560 rs
Cost of table = 700 rs
________________________

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devadakshan: see we moved the x to LHS and all othrr terms to RHS

devadakshan: ryt??

Nishakumarichaurasia: Yes

devadakshan: keep as such..... that is equation one(1)

Nishakumarichaurasia: Yex

Nishakumarichaurasia: Yes

devadakshan: next in equation (2) there u put the value of x from equation (3)

Nishakumarichaurasia: Oh yaa know i understood thankyou

devadakshan: hmm :-)

Nishakumarichaurasia: Thanks

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