if cosx.cos x = sinx.tanx then find the value of cos^6x -cos^2x
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Answer:
cosx×cosx= cos²x-----1
cox^6x= (cos²x)³-----2
cos²x=sinx.tanx (given)
Therefore,
cos^6x - cos²x
= (cos²x)³ - sinx.tanx (from 1, 2 and given)
= (sinx.tanx)³ - sin.tanx
= sin³x.tan³x - sinx.tanx
=sinx.tanx(sin²x.tan²x - 1) (by taking common outside)
HOPE THIS HELPS YOU :)
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