Math, asked by aastha4891, 1 year ago

If cosx=cosa.cosb thenprove that
tan[x+a÷2].tan [x-a÷2]=tan^2b/t2

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Answered by simran1313
2
i am unable to understand answer
simran1313: i am unable to understand last words of questiom
Answered by Anonymous
3

Answer:

There is a '+' in the fourth step in the denominator (cos(x+a+x-a)/2+cos(x+a-x+a)/2)

Step-by-step explanation:

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