Question

If cotФ-1÷cotФ+1 = 1-√3÷1+√3, then find the acute angle Ф

Answer 1

Hey dear!!

cotФ-1÷cot Ф+1 = 1-√3÷1+√3

LHS = (cot Ф - 1 )÷( cot Ф + 1)

=( 1/ tan Ф - 1 ) ÷ ( 1/tan Ф + 1)

={(1 - tan Ф) / tan Ф} ÷ {( 1 + tan Ф) / tan Ф}

= (1 - tan Ф) ÷ ( 1 + tan Ф)

RHS = ( 1 - √3) ÷ (1 + √3)

On comparing both the sides, we got the value of tan Ф.

tan Ф = √3

tan Ф = tan 60°

Therefore , the value of acute angle Ф = 60°.

Hope it helps! ^^

Answer 2

Answer:

tan60 degree is the correct answer