Math, asked by pruthviii, 1 year ago

if 3x-4/x =4 and x!=0;find : 27x cube -64/x cube
if 3x-4/x =4 and x!=0;find : 27x cube -64/x cube

Answers

Answered by kaustavmitra
72
here is your answer.
27 x^3 - 64/x^3
= (3x)^3 - (4/x)^3
= (3x-4/x)^3 + 3*3x*4/x*(3x - 4/x)
= 4^3+(36*4)
= 64+144
= 208(answer)
Answered by cutiee65
62
here is your answer please mark my answer as brain list
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