Question

if cot^2 a-3=0, find (1)sin2a (2) cos3a

Answer 1

Step-by-step explanation:

cot^2 A = 3

cosec^2 A - 1 = 3

1 / sin^2 A = 4

sin^2 A = 1/4

sinA = 1/2 = sin 30 Deg

A = 30 Deg

∴ sin 2A = sin 2*30 Deg = sin 60 deg

= (3^1/3) /2

∴ cos 3A = cos 90 Deg = 0

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