Math, asked by vikramq4961, 1 year ago

If cotθ=√3, find the value of (cosec^2θ+cot^2θ)/(cosec^2θ-cot^2θ)

Answers

Answered by Shriabhi344
0

Cot teeta =√3
Cot teeta=cot 30 (because cot 30 value is √3)
So,
Cosec2teeta+cot2teeta/cosec2teeta-cosec2teeta
=Cosec(2*30)+cot(2*30)/cosec(2*30)+cot(2*30)
=Cosec60+cot60/cosec60+cot60
=2/√3+1/√3/2/√3-1/√3
=3/√3/1/√3
=3
Hope this answers will be useful for you vicky

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