Question

If cot θ = 7/8, evaluate :

(i) (1 + sin θ)(1 – sin θ)

(1+cos θ)(1-cos θ)

(ii) cot2 θ​

Answer 1

Answer:

Land / perpendicular = cot theta

Hyperbolic= √ 7 square+ 8 square

= √113

Step-by-step explanation:

(i) (1 + sin θ)(1 – sin θ)(1+cos θ)(1-cos θ) = (1- sin square θ)(1- cos squareθ)

= (cos squareθ) (sin squareθ) = √(7/113) squar. × √(8/113) square)

= (7× 8)/113× 113

=56/12769