Question

if cot A = 4/3 then find the value of sinA, secA, and cosrcA​

Answer 1

in a  triangle ABC right angled at b

cot a= BC/AB

4/3=bc/ab

let bc be 4x and ab be 3x

by pythagoras theorem

ac=5x

sin A=AB/AC

= 3x/5x

=3/5

sec A=AC/BC

=5x/4x

=5/4

cosec A=1/Sin A

=5/3