If cot a is equal to 12 by 5 then find the value of bracket open Sin A + Cos A bracket of force
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Answered by
1
cot A = 12/5
i.e , cos A/sin A = 12/5
therefore , cos A = 12 , sin A = 5
sin A + cos A = 5+12 = 17
i.e , cos A/sin A = 12/5
therefore , cos A = 12 , sin A = 5
sin A + cos A = 5+12 = 17
Answered by
0
cos A /sin A = 5/12
cos A=5
sinA= 12
add them
=5+12
=17
cos A=5
sinA= 12
add them
=5+12
=17
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