Question

If cot a is equal to b by a prove that 2 sec a + 1 upon cos a + 2 is equal to root over a square + b square by b

Answer 1

Given :- If cot A is equal to b/a . prove that (2sec A + 1)/(cos A + 2) is equal to √(a² + b²) / b .?

Solution :-

→ cot A = b/a = Base / Perpendicular .

So, By pythagoras theorem,

→ Hypotenuse = √(B² + P²) = √(b² + a²) => √(a² + b²) .

Then,

• sec A = Hypotenuse / Base = √(a² + b²) / b .

Now,

→ (2sec A + 1)/(cos A + 2)

→ {2(1/cos A) + 1} / (cos A + 2)

→ {(2 + cos A) / cos A)} / (cos A + 2)

→ (cosA + 2) / cos A * (cos A + 2)

→ 1/cos A

→ sec A

→ √(a² + b²) / b (Proved).

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Answer 2

Step-by-step explanation:

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