Question

if cot B =5by 4,then show that cosec^2B=1+cot^2B

Answer 1

cot B=5/4

cot² B=(5/4)²=25/16

cot B=base/perpendicular

base/perpendicular=5/4

therefore,

hypotenuse=√(41)

by Pythagoras theorem

cosec B=hypotenuse/perpendicular

cosec² B=41/16

Now,

(25/16)+1

=(25+16)/16

=41/16

hence proved

Answer 2

Answer:

Step-by-step explanatio