Math, asked by rishita8622, 1 year ago

If cot square A - 3 = 0 find sin 2A cos 3A

Answers

Answered by rbjayswal2
11

Answer:


Step-by-step explanation:

cot^2 A = 3

cosec^2 A - 1 = 3

1 / sin^2 A = 4

sin^2 A = 1/4

sinA = 1/2 = sin 30 Deg

A = 30 Deg

∴ sin 2A = sin 2*30 Deg = sin 60 deg

                                        = (3^1/3) /2

∴ cos 3A = cos 90 Deg = 0

Answered by arundhathik2006
1

sin2A = root 3 / 2

cos 3A = 0

Similar questions