If cot square A - 3 = 0 find sin 2A cos 3A
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Answered by
11
Answer:
Step-by-step explanation:
cot^2 A = 3
cosec^2 A - 1 = 3
1 / sin^2 A = 4
sin^2 A = 1/4
sinA = 1/2 = sin 30 Deg
A = 30 Deg
∴ sin 2A = sin 2*30 Deg = sin 60 deg
= (3^1/3) /2
∴ cos 3A = cos 90 Deg = 0
Answered by
1
sin2A = root 3 / 2
cos 3A = 0
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