Question

Solve:

3^2x + 9 = 10(1/3)^-x​

Answer 1

Answer:

Let's solve this

3^(2x+1)+9/9=10

Break power of 3 in two part

3^2x*3+9/9=10

Common 3 from numerator

3(3^2x+3)/9=10

Cancel 9 by 3

3^2x+3/3=10

Multiply denominator to right side

3^2x+3=30

3^2x=30–3=27

We can write 3^3=27

3^2x=3^3

Equate both sides

Then we will get

2x=3

X=3/2

X=1.5

Step-by-step explanation:

I hope my answer helps you...✌