Solve:
3^2x + 9 = 10(1/3)^-x
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Answer:
Let's solve this
3^(2x+1)+9/9=10
Break power of 3 in two part
3^2x*3+9/9=10
Common 3 from numerator
3(3^2x+3)/9=10
Cancel 9 by 3
3^2x+3/3=10
Multiply denominator to right side
3^2x+3=30
3^2x=30–3=27
We can write 3^3=27
3^2x=3^3
Equate both sides
Then we will get
2x=3
X=3/2
X=1.5
Step-by-step explanation:
I hope my answer helps you...✌
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