Question

if cot teta =1/root3 then show that 1-cos ^2 teta/2- sin^2 teta = 3/5

Answer 1

cot x  = 1/ √3 
x = 60 degrees

cos (x) = cos 60 = 1/2 
sin x  = sin 60 = √3 / 2 

1 - cos² x =  1 - 1/4 = 3/4 
2 - sin²x = 2 - 3/4 = 5/4 

1 - cos² x / 2 - sin²x = 3/5 

Answer 2

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