if cot theta =-3/4 and theta lies in the second quadrant , the. D Find the values of sin 2 Theta and cos 2 theta
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Given :-
- cot θ = (-3/4)
- θ lies in 2nd quadrant .
To Find :-
- sin 2θ = ?
- cos 2θ = ?
Solution :-
we know that,
- In second quadrant , sin θ is positive only .
- cot θ = Base / perpendicular .
- sin θ = P / H
- cos θ = B / H
- H² = B² + P²
so ,
→ B / P = (3/4)
→ B = 3
→ P = 4
then,
→ H = √(B² + P²)
→ H = √(3² + 4²)
→ H = √(9 + 16)
→ H = √25 = 5
therefore,
→ sin 2θ = 2 * sin θ * cos θ
→ sin 2θ = 2 * (P / H) * (B / H)
→ sin 2θ = 2 * (4/5) * (-3/5)
→ sin 2θ = (-24/25) (Ans.)
and,
→ cos 2θ = 2cos²θ - 1
→ cos 2θ = 2(-3/5)² - 1
→ cos 2θ = 2(9/25) - 1
→ cos 2θ = (18/25) - 1
→ cos 2θ = (18 - 25)/25
→ cos 2θ = (-7/25) (Ans.)
Learn more :-
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