Math, asked by ayaanarshan, 3 months ago

if cot theta =-3/4 and theta lies in the second quadrant , the. D Find the values of sin 2 Theta and cos 2 theta​

Answers

Answered by bademona004
0

Answer is given in picture, it it is useful

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Answered by RvChaudharY50
1

Given :-

  • cot θ = (-3/4)
  • θ lies in 2nd quadrant .

To Find :-

  • sin 2θ = ?
  • cos 2θ = ?

Solution :-

we know that,

  • In second quadrant , sin θ is positive only .
  • cot θ = Base / perpendicular .
  • sin θ = P / H
  • cos θ = B / H
  • H² = B² + P²

so ,

→ B / P = (3/4)

→ B = 3

→ P = 4

then,

→ H = √(B² + P²)

→ H = √(3² + 4²)

→ H = √(9 + 16)

→ H = √25 = 5

therefore,

→ sin 2θ = 2 * sin θ * cos θ

→ sin 2θ = 2 * (P / H) * (B / H)

→ sin 2θ = 2 * (4/5) * (-3/5)

→ sin 2θ = (-24/25) (Ans.)

and,

→ cos 2θ = 2cos²θ - 1

→ cos 2θ = 2(-3/5)² - 1

→ cos 2θ = 2(9/25) - 1

→ cos 2θ = (18/25) - 1

→ cos 2θ = (18 - 25)/25

→ cos 2θ = (-7/25) (Ans.)

Learn more :-

It sino + tano = m

tano - sino an

Then express the

values of m²-n² in terms

of M and N

https://brainly.in/question/13926306

tanA/(1-cotA) + cotA/(1-tanA)

https://brainly.in/question/16775946

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