Question

IF COT THETA=49/9,find the value of cosec theta and sin theta​

Answer 1

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Answer 2

Answer:

$cosecϴ = \frac{41}{9} \\ sinϴ = \frac{9}{41}$

Step-by-step explanation:

1+cot²ϴ=1

$1 + { (\frac{40}{9}) }^{2} = {cosec}^{2} ϴ \\ 1 + \frac{1600}{81} = {cosec}^{2} ϴ \\ \frac{1681}{81} = {cosec}^{2} ϴ \\ \sqrt{ \frac{1681}{81} } = \sqrt{ {cosec}^{2} } ϴ \\ {cosec}^{2} ϴ = \frac{41}{9}$

$sinϴ = \frac{1}{cosecϴ} \\ sinϴ = \frac{1}{ \frac{1}{cosecϴ} } \\ sinϴ = \frac{1}{ \frac{41}{9} } \\ sinϴ = \frac{1 \times9}{41} \\ sinϴ = \frac{9}{41}$

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