If cot theta+cos theta =x and cot theta-cos theta=y then x^2-y^2=
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Step-by-step explanation:
cot+cos=x
cot-cos=y
so,
x²-y²
(cot+cos)²-(cot-cos)²
=cot²+cos²+2cotcos-cot²-cos²+2cotcos
=4cotcos.......(1)
[xy=cot²-cos²
=(cos²-sin²cos²/sin²)
=cos²(1-sin²)/sin²
=cos²cos²/sin²
=cot²cos² ]
(1) x²-y²=4√xy
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