Question

If cot theta equal to one by root 3 so that 1 - cos square theta by 2 minus sin square theta​

Answer 1

Cot A=1/√3=Cot 60°

so, A=60°

now,

Cos 60=1/2

Sin 60=√3/2

therefore,

(1-cos²A)/(2-sin²A)=[1-(1/2)²]/[2-(√3/2)²]

=[1-(1/4)]/[2-(3/4)]=[(4-1)/4]/[(8-3)/4]

=(3/4)/(5/4)=3/5 Ans.✌️