Question

if cot theta is 3/4 find other trignomatric ratio​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge \underbrace \mathfrak{answer} \\ \\ cos \: \theta = \frac{3}{4} = \frac{adjacent \: side}{hypotenuse \: side} = \frac{ab}{ac} \\ \\ now \\ \\ pythagorus \:formula \\ \\ {bc}^{2} = {ac}^{2} - {ab}^{2} \\ \\ {bc}^{2} = {4}^{2} - {3}^{2} \\ \\ {bc}^{2} = 16 - 9 \\ \\ {bc}^{2} = 7 \\ \\ bc = \sqrt{7} \\ \\ other \: \: ratios \\ \\ sin \: \theta \: = \frac{bc}{ac} = \frac{ \sqrt{7} }{4} \\ \\ tan \: \theta = \frac{ab}{bc} = \frac{3}{ \sqrt{7} } \\ \\ cosec \: \theta = \frac{ac}{bc} = \frac{4}{ \sqrt{7} } \\ \\ sec \: \theta = \frac{ac}{ab} = \frac{3}{4} \\ \\ cot \: \theta = \frac{ab}{bc} = \frac{3}{ \sqrt{7} }$